If the volume of a right circular cone of height 9 cm is 48π cm^{3}, find the diameter of its base.

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#### Solution

Height (*h*) of cone = 9 cm

Let the radius of the cone be *r*.

Volume of cone = 48π cm^{3}

`rArr1/3pir^2h=48picm^3`

`rArr(1/3pir^2xx9)cm=48picm^3`

⇒ r^{2} = 16 cm^{2}

⇒ r = 4 cm

Diameter of base = 2*r* = 8 cm

Concept: Volume of a Right Circular Cone

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